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Andrey Dyukmedzhiev
17/3/2015 12:26:47 pm
Triangle with sides 5, 9, x yields 5 + 9 > x, so x < 14.
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Kateryna Grechan
17/3/2015 05:20:25 pm
got the same
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17/3/2015 02:51:41 pm
This is a quadrilateral problem, quad = 34, 10, 18, 10. We're being asked to solve for a half-diagonal of the quad constrained to an integer.
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Anand
18/3/2015 02:40:04 am
The same again. Any two sides of any triangle add up to more than the third side.
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James
18/3/2015 06:14:34 am
Two triangles (5, 9, x) and (5, x, 17). Hence 5 + 9 > x i.e. x<14 and 5 + x > 17 i.e. x> 12. By hypothesis (x an integer) x=13.
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